alma wma tarama

Question

Merhaba. alma 9 periyotluk ortalamanın wma 9 periyotluık ortalamayı yukarı kestiği bir tarama formülü yazar mısınız

Answer 1

Merhaba,

 

Aşağıdaki şekilde bir inceleyip deneyiniz.

 

sigma:=9;

offset:=0.85;

w0:= Exp(-Power(0-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w1:= Exp(-Power(1-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w2:= Exp(-Power(2-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w3:= Exp(-Power(3-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w4:= Exp(-Power(4-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w5:= Exp(-Power(5-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w6:= Exp(-Power(6-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w7:= Exp(-Power(7-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

w8:= Exp(-Power(8-ROUND(offset*8-0.5),2)/(2*Power(9/sigma,2)));

s0:= w0*Ref(C,-8);

s1:= w1*Ref(C,-7);

s2:= w2*Ref(C,-6);

s3:= w3*Ref(C,-5);

s4:= w4*Ref(C,-4);

s5:= w5*Ref(C,-3);

s6:= w6*Ref(C,-2);

s7:= w7*Ref(C,-1);

alma:=If((w0+w1+w2+w3+w4+w5+w6+w7+w8)>0,(s0+s1+s2+s3+s4+s5+s6+s7+w8*C)/(w0+w1+w2+w3+w4+w5+w6+w7+w8),C);

CROSS(alma,MOV(C,9,W))

Bilgilerinize.